Deflections Using Energy Methods

Deflections-Using-Energy-Methods

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Chapter:

Can’t say

Smaller

force method

1⁄2 (p1 Δ1 + p2 Δ2)

Non-yielding support, linear elastic material

Elastic limit is not exceeded

p1 dΔ1 + p2 dΔ2 + 1⁄2 dp1d Δ1

false

NL/AE

They are equal

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Topics

Deflections Using Energy Methods

What is relation between work done and complementary work done?

in most cases, for a given loading maximum stress and deflection of an indeterminate structure are ______ than that of a determinate one.

Flexibility coefficients are used in which of following method?

What will be external work performed during application of load?Δ = displacement caused when force is increased by a small amount P = external force applied N = internal force in member force applied L = length of member A = cross-sectional area of member E = Modulus of elasticity

In which of following cases, is this orem applicable?

This method can be applied when:-

What will be work done during additional application of dp1?Δ = displacement caused when force is increased by a small amount P = external force applied N = internal force in member force applied L = length of member A = cross-sectional area of member E = Modulus of elasticity

Redundant forces are calculated in last step while using force method. State wher above statement is true or false.

Internal deformation caused by real loads will be in a linear elastic member:-

What is relation between work done by external loads and work done by internal loads.

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¹⁄₂ (p1 Δ1 + p2 Δ2)

p1 dΔ1 + p2 dΔ2 + ¹⁄₂ dp1d Δ1

What will be external work performed during application of load?
Δ = displacement caused when force is increased by a small amount
P = external force applied
N = internal force in member force applied
L = length of member
A = cross-sectional area of member
E = Modulus of elasticity

What will be work done during additional application of dp1?
Δ = displacement caused when force is increased by a small amount
P = external force applied
N = internal force in member force applied
L = length of member
A = cross-sectional area of member
E = Modulus of elasticity

Redundant forces are calculated in last step while using force method.
State wher above statement is true or false.