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You need to login to ask any Questions from chapter Equilibrium-of-a-Particle of Engineering-Mechanics

Chapter:

Equilibrium-of-a-Particle

1. In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AB section.

$In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AB section.\r\n$

900N 693N 646N 0N

693N

As system is in equilibrium so we need to balance forces. So when applying condition of net force to be zero in y direction, we get FAB cos30 = (2/3)*900. This gives us force along AB be 693N.

Hint Answer

2. An electromagnet crane is carrying electromagnet with help of three cables. But electromagnet is not stable because of wind. What is science behind cause?

The wind is making the net force of the body equal to a non-zero value The wind is making the net force of the body equal to zero value The wind is making the net force of the body equal to a non-zero value but is supporting the equilibrium The wind is making the net force of the body equal to zero value and supporting equilibrium

The wind is making the net force of the body equal to a non-zero value

Anybody is in equilibrium only if net force along three axis is zero. But in this case, wind is not helping body to do so. The science behind this is that resultant forces are being equated to a non-zero value by wind. Hence unstable.

Hint Answer

3. If resolved force or force which you get as answer after solving question is negative, n what does this implies?

The force is in the reverse direction w.r.t the direction set in the free body diagram The force is not in the reverse direction w.r.t the direction set in the free body diagram The force component is not possible The force is possible, but in the direction perpendicular to the resultant force

The force is in the reverse direction w.r.t the direction set in the free body diagram

The negative sign implies things in opposite manner. If force is coming negative this doesn?t mean that it is impossible. But it means that force is in opposite direction w.r.t direction set by you in free body diagram.

Hint Answer

4. Determine value of q, parallel to z-axis. That is point of intersection of projections of points A, B and C parallel to xy plane. With distance between tri-section point and points A, B and C be equal to 0.6m.

$Determine value of q, parallel to z-axis. That is point of intersection of projections of points A, B and C parallel to xy plane. With distance between tri-section point and points A, B and C be equal to 0.6m.\r\n$

51.9cm 51.9mm 51.9m 5.19mm

51.9cm

The application of equilibrium equation will yield result. That is resultant along z-axis will remain zero. Which give value of ? as 50?. And refore q=51.9cm.

Hint Answer

5. We first make equilibrium equations and n free body diagram and n solve question.

True False

False

We first make free body diagram and n we make equilibrium equations to satisfy given conditions. This helps us to solve question easily. As this reduces part of imagination and increases accuracy too.

Hint Answer

6. When body is in equilibrium n which of following is true?

We equate all the components of the forces acting on the body equal to their resultant vector’s magnitude We equate all the components of the forces acting on the body equal to their resultant vector’s magnitude square We equate all the components of the forces acting on the body equal to their resultant vector’s magnitude square root We equate all the components of the forces acting on the body equal to zero

We equate all the components of the forces acting on the body equal to zero

Yes, we equate all components of three axis equal to zero. That is resultant of forces along three axis are being equated to zero. This brings in that re is no net force in any direction. Hence equilibrium.

Hint Answer

7. Find tension in cable AC.

$Find tension in cable AC.\r\n$

23.6N 55N 89N -29N

23.6N

First represent forces in ir vector form. Then equate net sum of forces in x, y and z directions to be zero. You will get FB = FC and 2(.848) = 40N. This gives answer as 23.6N.

Hint Answer

8. ∑Fx=0, ∑Fy=0 and ∑Fz=0 are vector equations.

True False

False

The answer is false as equations asked are scalars. As we make net sum of forces along axis equal to zero. Of course this equation comes from solving vector forms, but still, result is a scalar, hence equations are scalar.

Hint Answer

9. In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AD section.

$In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AD section.\r\n$

900N 693N 646N 0N

900N

As system is in equilibrium so we need to balance forces. So when applying condition of net force to be zero in z direction, we get (2/3)FAD = 600N. This gives us force along AD be 900N.

Hint Answer

10. If anybody is tied to three or more ropes, and n is allowed to achieve its equilibrium. Then equilibrium achieved is achieved w.r.t what?

The three axis of the body The ground The ropes direction The weight direction

The ground

Yes, equilibrium is being achieved w.r.t ground. Like motion, w.r.t ground need be zero. That is relative velocity of object or body must be zero w.r.t ground. This means motion is in equilibrium.

Hint Answer

Nexttt

All Chapters

View all Chapter and number of question available From each chapter from Engineering-Mechanics

Force Vectors

Equilibrium of a Particle

Equilibrium of a Particle

Force System Resultants

Force System Resultants

Equilibrium of a Rigid Body

Equilibrium of a Rigid Body

Structural Analysis

Structural Analysis

Internal Forces

Internal Forces

Friction

Centre of Gravity and Centroid

Centre of Gravity and Centroid

Moments of Inertia

Moments of Inertia

Principle of Virtual Work

Principle of Virtual Work

Topics

This Chapter Equilibrium-of-a-Particle consists of the following topics

Equilibrium of a Particle

In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AB section.

$In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AB section.\r\n$

;

An electromagnet crane is carrying electromagnet with help of three cables. But electromagnet is not stable because of wind. What is science behind cause?

If resolved force or force which you get as answer after solving question is negative, n what does this implies?

Determine value of q, parallel to z-axis. That is point of intersection of projections of points A, B and C parallel to xy plane. With distance between tri-section point and points A, B and C be equal to 0.6m.

$Determine value of q, parallel to z-axis. That is point of intersection of projections of points A, B and C parallel to xy plane. With distance between tri-section point and points A, B and C be equal to 0.6m.\r\n$

;

We first make equilibrium equations and n free body diagram and n solve question.

When body is in equilibrium n which of following is true?

Find tension in cable AC.

$Find tension in cable AC.\r\n$

;

∑Fx=0, ∑Fy=0 and ∑Fz=0 are vector equations.

In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AD section.

$In diagram given below, coordinates of D is (1, -2, 2), C (-2, 0, 0) and B are as shown. The dark region is cables holding weight of 600N at origin. Find tension in AD section.\r\n$

;

If anybody is tied to three or more ropes, and n is allowed to achieve its equilibrium. Then equilibrium achieved is achieved w.r.t what?

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