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You need to login to ask any Questions from chapter Liquid-Extraction of Mass-Transfer

Chapter:

Liquid-Extraction

1. Find representation X.

$Find representation X.\r\n$

Extract Raffinate Residue None of the mentioned

Extract

The expected solutes are extracted from liquid by solvent is more in extract phase.

Hint Answer

2. Find mixture M in kg if R is 4 kg and E is 10 kg, where E is extract and R is raffinate.

$Find mixture M in kg if R is 4 kg and E is 10 kg, where E is extract and R is raffinate.\r\n$

6 kg 10 kg 14 kg 20 kg

14 kg

Mixture = Raffinate + Extract = 10 + 4 = 14 kg.

Hint Answer

3. Find process.

$Find process.\r\n$

Single stage batch process Single stage continuous process Multistage continuous process None of the mentioned

Single stage continuous process

Here stage used is one and re is a continuous input and output so process is a single stage continuous process.

Hint Answer

4. Solvent lean phase are known as

Extract Raffinate Residue None of the mentioned

Raffinate

The extracted solute will be rich in a solvent rich phase known as extract. Remaining small quantity of solute present in solvent lean phase is known as raffinate.

Hint Answer

5. By analysing this extraction equilibrium triangle, find solvent requirement range.

$By analysing this extraction equilibrium triangle, find solvent requirement range.\r\n$

Less solvent More solvent No solvent None of the mentioned

More solvent

In this pair configuration, we need more solvent because capacity to extract solute by solvent is less.

Hint Answer

6. If pure solvent is used find value of “ys” by analysing below single stage extractor.

$If pure solvent is used find value of “ys” by analysing below single stage extractor.\r\n \r\nWhere, F,S are feed and solvent$

Where, F,S are feed and solvent

0 1 0-1 None of the mentioned

0

Pure solvent in sense no solute present initially so ys= 0.

Hint Answer

7. Find representation A for extraction process.

$Find representation A for extraction process.\r\n$

Pure component A Pure component B Pure component C None of the mentioned

Pure component A

At A composition of A is 100% so solution will be pure A.

Hint Answer

8. The Azeotropic composition of solute makes extraction process economical.

True False

False

For Azeotropic composition, additional solvent is required to alter azeotropes formations.

Hint Answer

9. Find pure solvent rate if feed ( F= 100 kmol/hr) composition is 0.65 and mixture solute composition is 0.5.

10 kmol/hr 20 kmol/hr 30 kmol/hr 40 kmol/hr

10 kmol/hr

S/F = 0.65- 0.5/0.5 -0
= 0.3
= 100 x 0.3 = 30 kmol/hr.

Hint Answer

10. In extract, usage of solvent should be less.

True False

True

If less solvent is used we can reduce heat cost for separation by distillation in extract phase.

Hint Answer

Nexttt

All Chapters

View all Chapter and number of question available From each chapter from Mass-Transfer

Modes and Diffusion

Modes and Diffusion

Interphase Mass Transfer

Interphase Mass Transfer

Equipment for Gas-Liquid Operations

Equipment for Gas-Liquid Operations

Humidification Operations

Humidification Operations

Gas Absorption

Distillation

Liquid Extraction

Liquid Extraction

Drying

Leaching and Mass Transfer Co-efficients

Leaching and Mass Transfer Co-efficients

Diffusion in Solids and Molecular Diffusion in Fluids

Diffusion in Solids and Molecular Diffusion in Fluids

Topics

This Chapter Liquid-Extraction consists of the following topics

Liquid Extraction

Find representation X.

$Find representation X.\r\n$

;

Find mixture M in kg if R is 4 kg and E is 10 kg, where E is extract and R is raffinate.

$Find mixture M in kg if R is 4 kg and E is 10 kg, where E is extract and R is raffinate.\r\n$

;

Find process.

$Find process.\r\n$

;

Solvent lean phase are known as

By analysing this extraction equilibrium triangle, find solvent requirement range.

$By analysing this extraction equilibrium triangle, find solvent requirement range.\r\n$

;

If pure solvent is used find value of “ys” by analysing below single stage extractor.

$If pure solvent is used find value of “ys” by analysing below single stage extractor.\r\n \r\nWhere, F,S are feed and solvent$

Where, F,S are feed and solvent

;

Find representation A for extraction process.

$Find representation A for extraction process.\r\n$

;

The Azeotropic composition of solute makes extraction process economical.

Find pure solvent rate if feed ( F= 100 kmol/hr) composition is 0.65 and mixture solute composition is 0.5.

In extract, usage of solvent should be less.

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