Given object is point top view gives distance from vertical plane (15) and front view gives distance from horizontal plane (10) both are placed overlapped in orthographic projection since planes need to rotate to draw projection as object is placed in 2nd quadrant.

Here given two points such that joining line is perpendicular to vertical plane in 3rd quadrant asked side view and top view. The views in any quadrant will remain same but relative positions in projection will change accordingly quadrant.

Since point is 6 m away from profile plane distance from point to xy reference line will be 6 m. And n point is a distance of 6 from profile plane distance from reference line and point will be 6, sum is 12.

Side view is obtained by turning profile plane along hinge with vertical parallel to vertical plane. Side view and front view have same distance from a reference line. Sum of distances from point to vertical plane and profile plane gives following that is 15+8 = 23 dm.

Given point is in 2^nd quadrant. The front view and side view lie parallel to horizontal plane when orthographic projections are drawn. The distance from side view to vertical reference is 13 and distance from front view to profile plane is 13. Sum is 13+13= 26.

Given object is point top view gives distance from vertical plane (15) and front view gives distance from horizontal plane (10) both are placed overlapped in orthographic projection since planes need to rotate to draw projection as object is placed in 4th quadrant.

Since point is 12 units away from profile plane distance from point to xy reference line will be 12 units. And n point is at a distance of 12 units from profile plane distance from reference line and point will be 12, sum is 24.

Given point is in 2^nd quadrant. The front view and side view lie parallel to horizontal plane when orthographic projections are drawn. The distance from side view to vertical reference is 12 and distance from front view to profile plane is 13. Sum 12 + 13 =25.

Since point is 2 units away from profile plane distance from point to reference line will be 2 units. And n point is at a distance of 8 units from vertical plane distance from reference line and point will be 8, sum is 10.

Since point is 50 cm away from horizontal plane distance from point to xy reference line will be 50 cm. And n point is at distance of 50 cm from vertical plane distance from reference line and point will be 50 cm, sum is 100 cm.