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Structural-engineering-important-exam-questions-II

1.
\r\n AB = 12m, BC= 8m\r\n Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.\r\n FEM represent fixed end moments.What will be value of rotation at point D?\r\n

AB = 12m, BC= 8m
Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.
FEM represent fixed end moments.
What will be value of rotation at point D?


Hint Answer

2.
\r\n \r\n \r\n AB = 12m, BC = 15m, CD = 18m\r\n Load of 40 kN is acting at joint B as shown.\r\n EI is constant throughout frame.\r\n All force options are given in KN and all moment options are given in KN-M.\r\n FEM represent fixed end moments.What will be value of rotation at point B?\r\n

AB = 12m, BC = 15m, CD = 18m
Load of 40 kN is acting at joint B as shown.
EI is constant throughout frame.
All force options are given in KN and all moment options are given in KN-M.
FEM represent fixed end moments.
What will be value of rotation at point B?


Hint Answer

3.
\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.What will be value of rotation at point B?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
What will be value of rotation at point B?


Hint Answer

4. Which of following methods for solving indeterminate structures are easiest for computational purposes?


Hint Answer

5.
\r\n AB = 12m, BC= 8m\r\n Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.\r\n FEM represent fixed end moments.What will be one of extra condition, which we will get if we conserve moment near joint C?\r\n

AB = 12m, BC= 8m
Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.
FEM represent fixed end moments.
What will be one of extra condition, which we will get if we conserve moment near joint C?


Hint Answer

6.
\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.What will be value of mDC?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
What will be value of mDC?


Hint Answer

7.
\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.How many deflection unknowns will be re in this case for which we would need equations?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
How many deflection unknowns will be re in this case for which we would need equations?


Hint Answer

8. A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.
All moment options are given in kN-M.
A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.\r\n All moment options are given in kN-M.\r\n \r\n What will be value of mAB, after solving se equations?\r\n
What will be value of mAB, after solving se equations?


Hint Answer

9. A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.
All moment options are given in kN-M.
A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.\r\n All moment options are given in kN-M.\r\n \r\n What will be value of mCB, after solving se equations?\r\n
What will be value of mCB, after solving se equations?


Hint Answer

10.
\r\n A and C are fixed supports. M acts at point B in clockwise direction. AB = BC = L. EI is constant throughout frame.\r\n What will be value of Mba?\r\n

A and C are fixed supports. M acts at point B in clockwise direction. AB = BC = L. EI is constant throughout frame.

What will be value of Mba?


Hint Answer

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Topics

This Chapter Structural-engineering-important-exam-questions-II consists of the following topics

Displacement Method of Analysis: Slope-Deflection Equations

\r\n AB = 12m, BC= 8m\r\n Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.\r\n FEM represent fixed end moments.What will be value of rotation at point D?\r\n

AB = 12m, BC= 8m
Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.
FEM represent fixed end moments.
What will be value of rotation at point D?

;

\r\n \r\n \r\n AB = 12m, BC = 15m, CD = 18m\r\n Load of 40 kN is acting at joint B as shown.\r\n EI is constant throughout frame.\r\n All force options are given in KN and all moment options are given in KN-M.\r\n FEM represent fixed end moments.What will be value of rotation at point B?\r\n

AB = 12m, BC = 15m, CD = 18m
Load of 40 kN is acting at joint B as shown.
EI is constant throughout frame.
All force options are given in KN and all moment options are given in KN-M.
FEM represent fixed end moments.
What will be value of rotation at point B?

;

\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.What will be value of rotation at point B?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
What will be value of rotation at point B?

;

Which of following methods for solving indeterminate structures are easiest for computational purposes?

;

\r\n AB = 12m, BC= 8m\r\n Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.\r\n FEM represent fixed end moments.What will be one of extra condition, which we will get if we conserve moment near joint C?\r\n

AB = 12m, BC= 8m
Assume EI to be constant throughout. All moment options are given in N-m and all force options are given in N.
FEM represent fixed end moments.
What will be one of extra condition, which we will get if we conserve moment near joint C?

;

\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.What will be value of mDC?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
What will be value of mDC?

;

\r\n AB = BC = CD = 20m\r\n All moment options are given in KN/m and all rotations in rad.\r\n EI is constant.How many deflection unknowns will be re in this case for which we would need equations?\r\n

AB = BC = CD = 20m
All moment options are given in KN/m and all rotations in rad.
EI is constant.
How many deflection unknowns will be re in this case for which we would need equations?

;

A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.
All moment options are given in kN-M.
A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.\r\n All moment options are given in kN-M.\r\n \r\n What will be value of mAB, after solving se equations?\r\n
What will be value of mAB, after solving se equations?

;

A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.
All moment options are given in kN-M.
A is a fixed support, while B and C are roller supports. Uniformly distributed load of 2KN/m is acting on span AB. Load of 12 kN acts at a point between B and C. AB = 24m, BC = 8m. Load of 24KN acts at centre of BC.\r\n All moment options are given in kN-M.\r\n \r\n What will be value of mCB, after solving se equations?\r\n
What will be value of mCB, after solving se equations?

;

\r\n A and C are fixed supports. M acts at point B in clockwise direction. AB = BC = L. EI is constant throughout frame.\r\n What will be value of Mba?\r\n

A and C are fixed supports. M acts at point B in clockwise direction. AB = BC = L. EI is constant throughout frame.

What will be value of Mba?

;