So let's solve now,
A's 1 day work = $$\frac{1}{{18}}$$
B's 1 day work = $$\frac{1}{9}$$ [because B take half time than A]
(A + B)'s one day work
$$\eqalign{ & = {\frac{1}{{18}} + \frac{1}{9}} \cr & = {\frac{{1 + 2}}{{18}}} \cr & = \frac{1}{6} \cr} $$

Let number of pages typed in one hour by P, Q and R be x, y and z respectively
Then,
$$\eqalign{ & \Rightarrow x + y + z = \frac{{216}}{4} \cr & \Rightarrow x + y + z = 54z.....{\text{(i)}} \cr & {\text{ }}z - y = y - x \cr & \Rightarrow 2y = x + z.....{\text{(ii)}} \cr & {\text{ }}5z = 7x \cr & \Rightarrow x = \frac{5}{7}z......{\text{(iii)}} \cr} $$
Solving (i), (ii) and (iii), we get
$$\eqalign{ & x = 15, \cr & y = 18,{\text{ }} \cr & z = 21 \cr} $$

$$\eqalign{ & \left( {{\text{A}} + {\text{B}} + {\text{C}}} \right){\text{'s 1 day's work}} = \frac{1}{4} \cr & {\text{A's 1 day's work}} = \frac{1}{{16}} \cr & {\text{B's 1 day's work}} = \frac{1}{{12}} \cr & \refore {\text{C's 1 day's work}} \cr & = \frac{1}{4} - \left( {\frac{1}{{16}} + \frac{1}{{12}}} \right) \cr & = \left( {\frac{1}{4} - \frac{7}{{48}}} \right) \cr & = \frac{5}{{48}} \cr & {\text{So, C alone can do work in }} \cr & = \frac{{48}}{5} \cr & = 9\frac{3}{5}{\text{ days}} \cr} $$

L.C.M. of Total Work = 60
One day work of P + Q = $$\frac{{60}}{{6}}$$ = 10 unit/day efficiency
One day work of Q + R = $$\frac{{60}}{{\frac{{60}}{7}}}$$ = 7 unit/day efficiency
$$\eqalign{ & \left( {{\text{Q}} + {\text{R}}} \right){\text{ 6 days work}} \cr & = 7 \times 6 \cr & = 42{\text{ units}} \cr} $$
Then in 3 days = total work = 18
$$\eqalign{ & {\text{P completes}} \cr & = 60 - 42 \cr & = 18{\text{ units}} \cr & {\text{P's efficiency}} \cr & = \frac{{18}}{3} \cr & = 6{\text{ units/day}} \cr & {\text{Q's efficiency}} \cr & = 10 - 6 \cr & = 4{\text{ units/day}} \cr & {\text{R's efficiency}} \cr & = 7 - 4 \cr & = 3{\text{ units/day}} \cr & {\text{P completes whole work in}} \cr & = \frac{{60}}{6} \cr & = {\text{10 days}} \cr & {\text{R completes whole work in}} \cr & = \frac{{60}}{3} \cr & = {\text{20 days}} \cr & {\text{Difference is}} \cr & = \left( {20 - 10} \right) \cr & = 10{\text{ days }} \cr} $$

Ratio of times taken by Sakshi and Tanya
= 125 : 100
= 5 : 4
Suppose Tanya takes x days to do work
5 : 4 :: 20 : x
⇒ $$x = {\frac{{4 \times 20}}{5}} $$
⇒ x = 16 days
Hence, Tanya takes 16 days to complete work

Ratio of times taken by A and B
$$\eqalign{ & = 100:80 \cr & = 5:4 \cr} $$
Suppose B takes x hours to do work
$$\eqalign{ & \Rightarrow 5:4::\frac{{15}}{2}:x \cr & \Rightarrow x = \left( {\frac{{4 \times 15}}{{2 \times 5}}} \right) \cr & \Rightarrow x = 6{\text{ hours}}{\text{}} \cr} $$

Let A and B toger take x hours to complete work.
Then, A alone takes (x + 8) hours
And
B alone takes $$\left( {{\text{x}} + \frac{9}{2}} \right)$$   hours to complete work
Then,
$$\eqalign{ & \Rightarrow \frac{1}{{\left( {x + 8} \right)}} + \frac{1}{{\left( {x + \frac{9}{2}} \right)}} = \frac{1}{x} \cr & \Rightarrow \frac{1}{{\left( {x + 8} \right)}} + \frac{2}{{\left( {2x + 9} \right)}} = \frac{1}{x} \cr & \Rightarrow x\left( {4x + 25} \right) = \left( {x + 8} \right)\left( {2x + 9} \right) \cr & \Rightarrow 2{x^2} = 72 \cr & \Rightarrow {x^2} = 36 \cr & \Rightarrow x = 6 \cr} $$

Baggage delivered by first belt in 1 minute
$$ = \left( {\frac{3}{5}} \right){\text{tons}}$$
Baggage delivered by second belt in 1 minute
$$ = \left( {\frac{1}{2}} \right){\text{tons}}$$
Baggage delivered by both belt in 1 minute
$$\eqalign{ & = \left( {\frac{3}{5} + \frac{1}{2}} \right){\text{tons}} \cr & = \frac{{11}}{{10}}{\text{ tons}} \cr & \refore {\text{Required time}} \cr & = \left( {33 \div \frac{{11}}{{10}}} \right){\text{ minutes}} \cr & = \left( {33 \times \frac{{10}}{{11}}} \right){\text{minutes}} \cr & = {\text{30 minutes}} \cr} $$

Let time taken by A alone in doing work be x days
∴ Time taken by B alone = 3x days
$$\eqalign{ & {\text{A's 1 day's work}} = \frac{1}{x} \cr & {\text{B's 1 days work}} = \frac{1}{{3x}} \cr & \because {\text{A and B toger finish}} \cr & = \frac{2}{5}{\text{work in 9 days}}{\text{.}} \cr} $$
∴ Time taken by A and B in doing whole work
$$\eqalign{ & = \frac{{9 \times 5}}{2} \cr & = \frac{{45}}{2}{\text{ days}} \cr} $$
According to given information we get
$$\eqalign{ & \refore \frac{1}{x} + \frac{1}{{3x}} = \frac{2}{{45}} \cr & \Rightarrow \frac{{3 + 1}}{{3x}} = \frac{2}{{45}} \cr & \Rightarrow \frac{4}{{3x}} = \frac{2}{{45}} \cr & {\text{By cross - multiply we get }} \cr & \Rightarrow 2 \times 3x = 4 \times 45 \cr & \Rightarrow x = \frac{{4 \times 45}}{{2 \times 3}} \cr & \Rightarrow x = 30{\text{ days}} \cr & {\text{Time taken by A}} \cr & = x{\text{ days}} \cr & = {\text{30 days}} \cr & \refore {\text{Time taken by B}} \cr & = 3x{\text{ days}} \cr & = 3 \times 30 \cr & = 90{\text{ days}} \cr} $$

$$\eqalign{ & {\text{C's}}\,{\text{1}}\,{\text{day's}}\,{\text{work}} \cr & = \frac{1}{3} - \left( {\frac{1}{6} + \frac{1}{8}} \right) \cr & = \frac{1}{3} - \frac{7}{{24}} \cr & = \frac{1}{{24}} \cr & {\text{A's}}\,{\text{wages:B's}}\,{\text{wages:C's}}\,{\text{wages}} \cr & = \frac{1}{6}:\frac{1}{8}:\frac{1}{{24}} \cr & = 4:3:1 \cr & \refore {\text{C's}}\,{\text{share}}\,{\text{(for}}\,{\text{3}}\,{\text{days}}\,{\text{)}} \cr & = Rs.\,\left( {3 \times \frac{1}{{24}} \times 3200} \right) \cr & = Rs.\,400 \cr} $$