Parameters are missing. Dimensional and Model Analysis

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Chapter:

1. Which among following is not a fundamental dimension?

[L] [M] [T] [kg]

[kg]

It is essential to adopt a consistent dimensional quantity. Thus, we adopt a basic form to categorize dimension quantities. For this purpose, we adopt a comparison of quantities in SI or MKS units.

Hint Answer

2. The fundamental dimensional quantities are related by________

Avagadaro’s law Newton’s second law Newtons first law Newton’s third law

Newton’s second law

Newton?s 2^nd law is most suitable one for determining dimensional quantities. We know that, F=ma. Where F = Force , m = mass in kg, and a= acceleration in m/s².

Hint Answer

3. Force can be written as______

[M][L][T]^-2 [M][L][T]² [M][L][T] [M][L][T]³

[M][L][T]^-2

Force can be written dimensionally by [F]= [M][L][T]^-2. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L][T]^-2.

Hint Answer

4. How can we write power using MLT system?

[M][L][T]^-2 [M][L]²[T]³ [M][L][T] [M][L][T]³

[M][L]²[T]³

Power can be written dimensionally by [M][L]2[T]³. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L]²[T]³.

Hint Answer

5. How can we write dynamic viscosity using MLT system?

[M][L][T]^-2 [M][L]²[T]³ [M][L]^-1[T]^-1 [M][L][T]³

[M][L]^-1[T]^-1

Dynamic viscosity can be written dimensionally by [M][L]-1[T]^-1. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L]^-1[T]^-1.

Hint Answer

6. How can we write kinematic viscosity using MLT system?

[M][L][T]^-2 [M]⁰[L]²[T]^-1 [M][L]^-1[T]^-1 [M][L][T]³

[M]⁰[L]²[T]^-1

Kinematic viscosity can be written dimensionally by [M]0[L]2[T]^-1. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M]⁰[L]²[T]^-1.

Hint Answer

7. How can we write momentum using MLT system?

[M][L][T]^-2 [M]⁰[L]²[T]^-1 [M][L][T]^-1 [M][L][T]³

[M][L][T]^-1

Momentum can be written dimensionally by [M][L][T]^-1. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L][T]^-1.

Hint Answer

8. How can we write specific weight using FLT system?

[F] [F][T] [F][L][T] [L]

[F]

Specific can be written dimensionally by [F]. This is by adopting basic SI or MKS units (FLT system). Where, [F] is mass, [L] is length and [T] is time. Thus, correct option is [F].

Hint Answer

9. How can we write specific mass using MLT system?

[M][L][T]^-2 [M]⁰[L]²[T]^-1 [M][L]^-3[T]⁰ [M][L][T]³

[M][L]^-3[T]⁰

Specific mass can be written dimensionally by [M][L]-3[T]⁰. This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L]^-3[T]⁰.

Hint Answer

10. How can we write energy using MLT system?

[M][L]²[T]² [M]⁰[L]²[T]^-1 [M][L]^-3[T]⁰ [M][L][T]³

[M][L]²[T]²

Energy or work can be written dimensionally by [M][L]2[T]². This is by adopting basic SI or MKS units. Where, [M] is mass, [L] is length and [T] is time. Thus, correct option is [M][L]²[T]².

Hint Answer

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All Chapters

View all Chapter and number of question available From each chapter from

Properties of Fluids

Properties of Fluids

Pressure and Its Measurement

Pressure and Its Measurement

Hydrostatic Forces on Surfaces

Hydrostatic Forces on Surfaces

Buoyancy and Floatation

Buoyancy and Floatation

Kinematics of Flow and Ideal Flow

Kinematics of Flow and Ideal Flow

Fluid Dynamics

Orifices, Mouthpieces, Notches and Weirs

Orifices, Mouthpieces, Notches and Weirs

Viscous Flow & Turbulent Flow

Viscous Flow & Turbulent Flow

Flow Through Pipes

Flow Through Pipes

Indicator Diagrams

Indicator Diagrams

Dimensional and Model Analysis

Dimensional and Model Analysis

Boundary Layer Flow & Forces on Sub-merged Bodies

Boundary Layer Flow & Forces on Sub-merged Bodies

Compressible Flow

Compressible Flow

Flow in Open Channels

Flow in Open Channels

Non Uniform Flow in Channels

Non Uniform Flow in Channels

Impact of Jets and Jet Propulsion

Impact of Jets and Jet Propulsion

Topics

This Chapter consists of the following topics

Dimensional and Model Analysis

Which among following is not a fundamental dimension?

The fundamental dimensional quantities are related by________

Force can be written as______

How can we write power using MLT system?

How can we write dynamic viscosity using MLT system?

How can we write kinematic viscosity using MLT system?

How can we write momentum using MLT system?

How can we write specific weight using FLT system?

How can we write specific mass using MLT system?

How can we write energy using MLT system?

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