.C Program to Find Number of Integers Divisible by 5 in a given range:

This is a C Program which calculates the number of integers divisible by 5 in the given range.

Problem Description

• This program takes the range as input and finds the number of integers divisible by 5 in the given range.

• Also finds the sum of all integers that are divisible by 5 in the given range.

Problem Solution

• Take the range as input.

• Find all the integers that gives remainder zero when divided by 5 and print them as output.

• Add all the integers that are divisible by 5 and print the sum.

• Also print the count of integers that are divisible by 5.

Program/Source Code

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This is a C Program which calculates the number of integers divisible by 5 in the given range.

Problem Description

• This program takes the range as input and finds the number of integers divisible by 5 in the given range.

• Also finds the sum of all integers that are divisible by 5 in the given range.

Problem Solution

• Take the range as input.

• Find all the integers that gives remainder zero when divided by 5 and print them as output.

• Add all the integers that are divisible by 5 and print the sum.

• Also print the count of integers that are divisible by 5.

Program/Source Code

/*
 * C program to find the number of integers divisible by 
 * 5 between the given range num1 and num2, where num1 < num2.
 *
 * Also find the sum of all these integer numbers which are divisible
 * by 5 and display the total.
 */
#include 
 
void main()
{
    int i, num1, num2, count = 0, sum = 0;
 
    printf("Enter the value of num1 and num2 \n");
    scanf("%d %d", &num1, &num2);
    /* Count the number and compute their sum*/
    printf("Integers divisible by 5 are \n");
    for (i = num1; i < num2; i++)
    {
        if (i % 5 == 0)
        {
            printf("%3d,", i);
            count++;
            sum = sum + i;
        }
    }
    printf("\n Number of integers divisible by 5 between %d and %d =
 %d\n", num1, num2, count);
    printf("Sum of all integers that are divisible by 5 = %d\n", sum);
}

Program Explanation

• Take the range as input and store it in the variables num1 and num2 respectively.

• Firstly initialize the variables count and sum to zero.

• Using the for loop, find all the integers that gives remainder zero when divided by 5 and print them consecutively.

• Along with this, increment both the variables i.e increment the variable count by 1 and variable sum by the number that is divisible by 5.

• Print the variables count and sum as output.

Output:

Case:1

Enter the value of num1 and num2

12 17

Integers divisible by 5 are

 15,

Number of integers divisible by 5 between 12 and 17 = 1

Sum of all integers that are divisible by 5 = 15

 

Case:2

Enter the value of num1 and num2

1 10

Integers divisible by 5 are

 5,10

Number of integers divisible by 5 between 1 and 10 = 2

Sum of all integers that are divisible by 5 = 15