Determine the size of the fillet welds needed for the strength of the plates in tension. `f_y=250\ MPa` and `f_u=410\ MPa`

Solution:

Here, the thickness of both plates is same. So, the size of welds is also same.

We know, the design strength of fillet weld is,

`f_(wd)=f_u/(root()(3)**gamma_(mw))`

`=410/(root()(3)**1.25)`

`=189.371\ MPa`

We Know, the minimum size of the weld is, `S_(m i n)=5\ mm` and the maximum size of the weld is weld is `S_(m a x)=10-1.5=8.5\ mm`

Now,

`S` is the average of the minimum and maximum value. i.e, `S=6.75~=7\ mm`

Hence, the size of the fillet weld is `7\ mm`

Solution:

Here, the thickness of both plates is same. So, the size of welds is also same.

We know, the design strength of fillet weld is,

`f_(wd)=f_u/(root()(3)**gamma_(mw))`

`=410/(root()(3)**1.25)`

`=189.371\ MPa`

We Know, the minimum size of the weld is, `S_(m i n)=5\ mm` and the maximum size of the weld is weld is `S_(m a x)=10-1.5=8.5\ mm`

Now,

`S` is the average of the minimum and maximum value. i.e, `S=6.75~=7\ mm`

Hence, the size of the fillet weld is `7\ mm`