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Design-of-sewers-Tutorial

Calculate diameter and discharge of a circular sewer laid at a slope of 1 in 500 when running half full with velocity of 2 m/sec. Take n =0.012

Solution:

We have, from Mannings formula,

`v=1/n R^(2/3) S^(1/2)`

or, `2=1/0.012 (d/4)^(2/3)(1/500)^(1/2)`

or, `d=1.572\ m`

And the discharge is,

`Q=AV`

`=1/2(pi**1.572^2)/4**2`

`=1.942\ m^3/s`

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This Chapter Design-of-sewers-Tutorial consists of the following topics

Calculate the velocity of flow and discharge in a circular sewer having diameter `1` m and laid at a gradient of `1:600` and
  • running full and
  • running half full.
Take N = 0.012.

Calculate diameter and discharge of a circular sewer laid at a slope of 1 in 500 when running half full with velocity of 2 m/sec. Take n =0.012

Calculate the diameter and velocity of circular sewer at a slope of 1 in 400 when running full at a discharge of 1.0 m 3 /sec. What will be discharge and velocity when flowing half full? Take n =0.012

Calculate the diameter and discharge of a circular sewer laid at a slope of 1 in 500 when running half full with velocity of 2 m/sec. Take n =0.012

Design of sewers Tutorial

Sanitary-Engineering