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Conic-Sections

Find coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.


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This Chapter Conic-Sections consists of the following topics

The center of ellipse is same as a vertex.

Find coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.

Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.

Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.

Conic Sections

Objective-Mathematics