The difference between two angles of a triangle is 24°. The average of same two angles is 54°. Which one of following is value of greatest angle of triangle?

Let a and b be the two angles in the question, with a > b. We are given that the difference between the angles is 24°.
? a ? b = 24
Since the average of the two angles is 54°, we have $$\frac{{{\text{a}} + {\text{b}}}}{2}$$  = 54
Solving for b in the first equation yields b = a ? 24, and substituting this into the second equation yields,
$$ {\frac{{\left\{ {{\text{a}} + \left( {{\text{a}} - 24} \right)} \right\}}}{2}} = 54$$
2a ? 24 = 54 × 2
2a ? 24 = 108
2a = 108 + 24
2a = 132
a = 66
Also,
b = a ? 24 = 66 ? 24 = 42
Now, let c be the third angle of the triangle. Since the sum of the angles in the triangle is
180°, a + b + c = 180°
Putting the previous results into the equation yields 66 + 42 + c = 180°
Solving for c yields c = 72°
Hence, the greatest of the three angles a, b and c is c, which equal.