The average price of 10 books is Rs.12 while average price of 8 of se books is Rs. 11.75. Of remaining two books, if price of one book is 60% more than price of or, what is price of each of se two books?

Total cost of 10 books = Rs. 120
Total cost of 8 books = Rs. 94
? The cost of 2 books = Rs. 26
Let the price of each book be x and y.
? x + y = 26 - - - - - -(1)
Given that the price of 1 book is 60% more than the other price
$$\eqalign{ & \left( {\frac{{160}}{{100}}} \right)y + y = 26 \cr & \Rightarrow y\left( {\frac{{160}}{{100}} + 1} \right) = 26 \cr & \Rightarrow y\left( {\frac{{160 + 100}}{{100}}} \right) = 26 \cr & \Rightarrow y = \frac{{\left( {26 \times 100} \right)}}{{260}} \cr & \Rightarrow y = 10 \cr & {\text{Substituting}}\,\,y = 10\,\,{\text{in }}{\kern 1pt} \left(1 \right){\text{we get}}, \cr & x + 10 = 26 \cr & x = 16 \cr} $$