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5(x + 3) = 25(3x - 4), n find value of x


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What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder?

5(x + 3) = 25(3x - 4), n find value of x

Three numbers which are co-prime to one another are such that the product of the first two is 551 and that of last two is 1073. The sum of the three numbers is:

5<sup>(x + 3)</sup> = 25<sup>(3x - 4)</sup>

then find the value of x</sup>

Number System Aptitude questions

Arithmetic-Aptitude