The sum of four consecutive even numbers is 748, The smallest among m is -

Let 'a' be the smallest even number
According to question
$$\eqalign{ & (a) + (a + 2) + (a + 4) + (a + 6) = 748 \cr & 4a + 12 = 748 \cr & 4a = 736 \cr & a = 184 \cr & \cr & {\bf{Alternate :}} \cr & {\text{Middle term }} = \frac{{748}}{4} = 187 \cr & \underline {184} \,\,\,\,\underline {186} \,\,\,\underline {188} \,\,\,\underline {190} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop {187}\limits^ \downarrow \cr & {\text{Smallest number = 184}} \cr} $$