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Properties-of-fluid

A square plate of size 1 m x 1m and weighing 350 N slides down an inclined plane with a uniform velocity of 1.5 m/s. The inclined plane is laid on a slope of 5 vertical to 12 horizontal and has an oil film of 1 mm thickness. Calculate dynamic viscosity of oil in poise.

Solution:

Here,

`v=1.5` m/s

`mu=?`

`A=1**1=1m^2`

`W=350\ N`

Now,

Here, `tan theta=5/12`

Thus,

`F= W sin theta=350 sin (22.62)=134.615\ N`

Now, the shear stress is, `tau=mu du/dy`

where, `tau=F/A=134.615`

Thus, `134.615=mu** 1.5/0.001`

or, `mu=0.08974` Ns/m

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This Chapter Properties-of-fluid consists of the following topics

Two large plane surface are 2.4 cm apart. The space between the surface is filled with glycerin having viscosity `8.1**10^(-1)` Ns/`m^2`. What force is required to drag a thin plate of surface area 0.5 `m^2` between that large plane surface at speed of 0.6 m/s. If the thin plate is at a distance of 0.8 m from one of the plane surface.

A square plate of size 1 m x 1m and weighing 350 N slides down an inclined plane with a uniform velocity of 1.5 m/s. The inclined plane is laid on a slope of 5 vertical to 12 horizontal and has an oil film of 1 mm thickness. Calculate dynamic viscosity of oil in poise.

A thin plate of very large area is placed in a gap of height h with oils of viscosities `mu^'` and `mu^''` on the two sides of the plate. The plate is pulled at a constant velocity V. Calculate the position of plate so that:

the shear force on the two sides of the plate is equal

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Assume viscous flow and neglect all end effects.

A square plate of size 1 m x 1m and weighing 350 N slides down an inclined plane with a uniform velocity of 1.5 m/s. The inclined plane is laid on a slope of 5 vertical to 12 horizontal and has an oil film of 1 mm thickness. Calculate the dynamic viscosity of oil in poise.

Properties of fluid

Fluid-Mechanics