In a large randomly mating population, only one person in $10,000$ is an albino. What will be frequency of a carrier person of albinism?

Albinism is an autosomal recessive genetic disorder. It is given that frequency of an albino in a population is $1$ in $10,000$, i.e., $\frac{1}{10000}$ or $0.0001$.
According to Hardy-Weinbery law $p^2+q^2+2pq=1$
where $p^2$ and $q^2$ are frequencies of homozygous dominant individuals and homozygous recessive individuals respectively and $2pq$ represents the frequency of carrier. $p$ and $q$ represent frequency of dominant and recessive allele respectively.
Now, $q^2=0.0001$
$q=\sqrt{0.0001}=0.01$
Also, $p+q=1$
$?p=0.99$
Hence, $2pq=2\times 0.01\times 0.99$
$=0.0198$ or $0.02$
$=2$%
Accordingly, $1$ person in $50$ will be a carrier of albinism.