What is quantity of cement (in kg) and of dry sand (in cubic meter) respectively required for preparing 1 cubic meter of wet cement mortar of 1 : 5 proportion?

Concept:

The following is parameters and properties of cement:

1. Bulk density of cement = 1440 kg/m3

2. Specific gravity of cement = 3.15

3. Weight of one bag of cement = 50 kg

4. Volume of cement bag = 50/1440 = 0.035 m3

5. Number of cement bags in 1 m3 = 30 approx.

6. Volume of dry mortar is 30% more than the volume of wet mortar.

∴ The volume of dry mortar = 1.3 × volume of wet mortar

Calculation:

1 m³ of wet cement mortar will correspond to 1.30 m³ of dry mortar

Sum of proportions = 1 + 5 = 6

Cement =$\frac{1.3}{6}=0.216{\mathrm{m}}^3$

1 m³ of cement = 1440 kg

So, 0.216 m³ to cement = 312 kg

Sand = $\frac{5\times 1.3}{6}=1.08{\mathrm{m}}^3$