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Internal Loadings Developed in Structural Members

Course: Structural Analysis — Practice MCQs, solutions, formulas & past entrance questions.

Courses › Structural Analysis › Internal Loadings Developed in Structural Members

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1. What will be shape of SFD in entire beam?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.
AB = BC = CD = DE = EF = FG = 2m

$What will be shape of SFD in entire beam?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n AB = BC = CD = DE = EF = FG = 2m\r\n \r\n \r\n$

Straight line Straight line with point of discontinuities Curve Curve with point of discontinuities

Straight line with point of discontinuities

Since load is not a function of x, so SFD will always be straight line. But, since load varies suddenly at some points, SFD will have discontinuities.

Hint Answer

2. How many points of discontinuities will be re in SFD of beam BC?
In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.
AB = 4m and BC = 8m.

$How many points of discontinuities will be re in SFD of beam BC?In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.\r\n AB = 4m and BC = 8m.\r\n \r\n \r\n$

0 1 2 3

0

Since re is no discreet loading on beam BC so, re won?t be any points of discontinuities in beam BC.

Hint Answer

3. Direction of shear force will always be towards x axis in this frame.
Sate wher above statement is true or false.
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$Direction of shear force will always be towards x axis in this frame.\r\nSate wher above statement is true or false.Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\nAB = 5m, BC = CD = 2m\r\n \r\n\r\n$

True False

False

Direction of shear force is always perpendicular to that of beam. In this frame, orientations of beams are different and so will be that of shear forces. One beam is parallel to x axis while or one is inclined at some angle.

Hint Answer

4. What will be internal moment generated at joint B due to above shown loading?
All options are given in KN and KN/M wherever applicable.
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$What will be internal moment generated at joint B due to above shown loading?All options are given in KN and KN/M wherever applicable.\r\n Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\n AB = 5m, BC = CD = 2m\r\n \r\n \r\n$

170 340 510 680

680

It can be found out by balancing moment about point B in part between points B and D.

Hint Answer

5. How many points of discontinuities will be re in SFD?
In following figure AB=BC=CD=2m, and DE=EF=1m.
A is a fixed support while C and F are of roller type. B and D are hinges.
All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.

$How many points of discontinuities will be re in SFD?In following figure AB=BC=CD=2m, and DE=EF=1m.\r\n A is a fixed support while C and F are of roller type. B and D are hinges.\r\n All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n \r\n \r\n$

1 2 3 4

2

2 discreet loads are applied in between beam (excluding starting and end points). So, 3 discontinuities will be re.

Hint Answer

6. What will be shape of SFD of beam BC?
In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.
AB = 4m and BC = 8m.

$What will be shape of SFD of beam BC?In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.\r\n AB = 4m and BC = 8m.\r\n \r\n \r\n$

Triangular Rectangular Trapezoid Arbitrary curve

Rectangular

There is no point of discontinuity, so curve will basically two end values. Since both comes out to be same in this case, shape will e rectangular.

Hint Answer

7. At what point would slope of BMD of beam AB be 0?
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$At what point would slope of BMD of beam AB be 0?Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\n AB = 5m, BC = CD = 2m\r\n \r\n \r\n$

A B In between Never

In between

Because at one in between point, shear force comes out to be zero.

Hint Answer

8. What will be support reaction generated by support A?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
AB = BC = CD = DE = EF = FG = 2m.

$What will be support reaction generated by support A?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n AB = BC = CD = DE = EF = FG = 2m.\r\n \r\n$

5 10 15 20

10

This can be found out by balancing force in part between joints A and B.

Hint Answer

9. What will be internal force generated at hinge D due to above loading?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
AB = BC = CD = DE = EF = FG = 2m.

$What will be internal force generated at hinge D due to above loading?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n AB = BC = CD = DE = EF = FG = 2m.\r\n \r\n$

5 10 15 20

10

We can separate part from point B to D. Now, we have internal load at B so, we can balance moment about point C and find out force at point D.

Hint Answer

10. What will be starting value of BMD?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.
AB = BC = CD = DE = EF = FG = 2m

$What will be starting value of BMD?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n AB = BC = CD = DE = EF = FG = 2m\r\n \r\n \r\n$

20 -20 5 -5

20

Bending moment at point A is +20KN/M. So, curve will start with +20.

Hint Answer

Nexttt

All Chapters

View all Chapter and number of question available From each chapter from structural-analysis

System Loading and Behavior

System Loading and Behavior

Structural Loads

Structural Loads

Analysis of Statically Determinate Structures and Trusses

Analysis of Statically Determinate Structures and Trusses

Analysis of Kinematically Determinate Structures & Plane Trusses

Analysis of Kinematically Determinate Structures & Plane Trusses

Internal Loadings Developed in Structural Members

Internal Loadings Developed in Structural Members

Analysis of Statically Indeterminate Structures by the Force Method

Analysis of Statically Indeterminate Structures by the Force Method

Beams and Frames Having Nonprismatic Member

Beams and Frames Having Nonprismatic Member

Truss, Beam and Plane Frame Analysis Using the Stiffness Method

Truss, Beam and Plane Frame Analysis Using the Stiffness Method

Additional Matrix Procedures

Additional Matrix Procedures

Topics

This Chapter internal-loadings-developed-in-structural-members consists of the following topics

Internal Loadings Developed in Structural Members

What will be shape of SFD in entire beam?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.
AB = BC = CD = DE = EF = FG = 2m

$What will be shape of SFD in entire beam?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n AB = BC = CD = DE = EF = FG = 2m\r\n \r\n \r\n$

;

How many points of discontinuities will be re in SFD of beam BC?
In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.
AB = 4m and BC = 8m.

$How many points of discontinuities will be re in SFD of beam BC?In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.\r\n AB = 4m and BC = 8m.\r\n \r\n \r\n$

;

Direction of shear force will always be towards x axis in this frame.
Sate wher above statement is true or false.
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$Direction of shear force will always be towards x axis in this frame.\r\nSate wher above statement is true or false.Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\nAB = 5m, BC = CD = 2m\r\n \r\n\r\n$

;

What will be internal moment generated at joint B due to above shown loading?
All options are given in KN and KN/M wherever applicable.
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$What will be internal moment generated at joint B due to above shown loading?All options are given in KN and KN/M wherever applicable.\r\n Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\n AB = 5m, BC = CD = 2m\r\n \r\n \r\n$

;

How many points of discontinuities will be re in SFD?
In following figure AB=BC=CD=2m, and DE=EF=1m.
A is a fixed support while C and F are of roller type. B and D are hinges.
All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.

$How many points of discontinuities will be re in SFD?In following figure AB=BC=CD=2m, and DE=EF=1m.\r\n A is a fixed support while C and F are of roller type. B and D are hinges.\r\n All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n \r\n \r\n$

;

What will be shape of SFD of beam BC?
In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.
AB = 4m and BC = 8m.

$What will be shape of SFD of beam BC?In following figure, point A has pin support, while point C has roller type support. Point B is a fixed end.\r\n AB = 4m and BC = 8m.\r\n \r\n \r\n$

;

At what point would slope of BMD of beam AB be 0?
Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.
AB = 5m, BC = CD = 2m

$At what point would slope of BMD of beam AB be 0?Point A is pin support and point D is roller type support. Uniform horizontal load of 80KN/m is acting on beam AB.\r\n AB = 5m, BC = CD = 2m\r\n \r\n \r\n$

;

What will be support reaction generated by support A?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
AB = BC = CD = DE = EF = FG = 2m.

$What will be support reaction generated by support A?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n AB = BC = CD = DE = EF = FG = 2m.\r\n \r\n$

;

What will be internal force generated at hinge D due to above loading?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
AB = BC = CD = DE = EF = FG = 2m.

$What will be internal force generated at hinge D due to above loading?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n AB = BC = CD = DE = EF = FG = 2m.\r\n \r\n$

;

What will be starting value of BMD?
In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.
BMD and SFD starts from point A.
AB = BC = CD = DE = EF = FG = 2m

$What will be starting value of BMD?In following figure, all supports are roller type and B and D are hinges. All options are given in KN and KN/M wherever applicable.\r\n BMD and SFD starts from point A.\r\n AB = BC = CD = DE = EF = FG = 2m\r\n \r\n \r\n$

;

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